In computer science and mathematics, the Josephus Problem (or Josephus permutation) is a theoretical problem. Following is the problem statement: There are n people standing in a circle waiting to be executed. The counting out begins at some point in the circle and proceeds around the circle in a fixed direction. In each step, a certain number of people are skipped and the next person is executed. The elimination proceeds around the circle (which is becoming smaller and smaller as. Das Josephus-Problem oder die Josephus-Permutation ist ein theoretisches Problem aus der Informatik oder Mathematik. Es werden nummerierte Objekte im Kreis angeordnet; dann wird, beginnend mit der Nummer , jedes -te Objekt entfernt, wobei der Kreis immer wieder geschlossen wird. Die Reihenfolge der entfernten Objekte wird als Josephus-Permutation bezeichnet You are encouraged to solve this task according to the task description, using any language you may know. Josephus problem is a math puzzle with a grim description: prisoners are standing on a circle, sequentially numbered fro

JosephusProblem Algorithm. Any questions do not hesitate to contact. /** * Author: Isaac * Date: 2009-04-06 * License: - * Source: * Description: Josephus problem */ /// Josephus problem, n people numbered from 1 to n stand in a circle. /// Counting starts from 1 and every k'th people dies /// Returns the position of the m'th killed people /// For example if n = 10 and k = 3, then the people. Josephus-Problem (Felder) Es stehen n Personen in einem Kreis. Die Personen sind nummeriert von 1 bis n. Beginnend bei Person Nummer p wird nun jede p-te Person aus dem Kreis entfernt und der Kreis danach sofort wieder geschlossen (jede Person behält dabei ihre anfänglich zugewiesene Nummer). Geben Sie die Nummern der entfernten Personen in der. I was reading the algorithm for the Josephus Problem. I came across the following algorithm : int josephusIteration(int n,int k) { int a=1; for(int i=1;i<=n;i++) { a=(a+k-1)%i+1; } return a; } I couldn't understand its logic. Suppose n=5 and k=2. i=1, a=1 i=2, a=1 i=3, a=3 i=4, a=1 i=5, a= Data Structure and Algorithm See more on: C Code Katas..... The Josephus Problem . Posted by Unknown On Saturday, July 10, 2010 2 comments /***** The Josephus Problem--> The Problem is known as the Josephus problem and postulates a group of. soldiers surrounded by an overwhelming enemy force. There is no hope for. victory without reinforcements, but there is only a single horse available. for.

- The Problem. This problem is named after Flavius Josephus a Jewish historian who fought against the Romans. According to Josephus he and his group of Jewish soldiers were cornered & surrounded by the Romans inside a cave, and they chose to murder and suicide inside of surrender and capture. They decided that all the soldiers will sit in a circle and starting from the soldier sitting at the first position every soldier will kill the soldier to their sequentially. So if there are 5.
- ated. N - the number of people. The result is a list in the order in which people are eli
- d, let's think about how the Josephus problem works by looking at a concrete example. Suppose we want to know josephus(n, 2). You can imagine we have n people lined up like this: 1 2 3 4 5
- CP Algoritmos, Algoritmos, cp algorithms brasil, CP Algoritmos, Data Structure, cp algorithms, Estrutura de dados, C++ e Algoritmos, CP Algorithms, cp algoritmos, cp.

* In computer science and mathematics, the Josephus problem (or Josephus permutation) is a theoretical problem related to a certain counting-out game*. A drawing for the Josephus problem sequence for 500 people and skipping value of 6. The horizontal axis is the number of the person. The vertical axis (top to bottom) is time (the number of cycle) After the loop has completed, we are left with a value for p that is one power of 2 greater than n. So we simply divide p by 2 to get the correct value. {% set p = p / 2 %} Now all that is left is to calculate L and plug it into the formula above to output the solution. {% set L = n - p %} { { (2 * L) + 1 } O (n log m) ALGORITHM FOR THE JOSEPHUS PROBLEM 263 We are interested in algorithms which, given integers n and m, generate the n : m Josephus Permutation. An obvious approach utilizes circular linked lists and has an 0 (n*m) running time. In Knuth mentions the existence of an O (n log n) algorithm which makes use of a balanced binary tree

I came across this interesting algorithm called the Josephus Problem. At the start, the problem presented was seemingly quite difficult to solve, however, the more I worked through the problem I found the solution could be eloquently expressed with a few lines of code. In fact, it appears to go over my head the first time. But, after doing some research, it really started to make me re-think how I approach problem-solving The original Josephus problem consisted of a circle of 41 men with every third man killed (,), illustrated above, where the outer number indicates the order in which a given man is killed. In order for the lives of the last two men to be spared, they must be placed at positions 31 (last) and 16 (second-to-last)

- The Josephus Problem is a famous mathematical puzzle that goes back to ancient times. There are many stories to go with the puzzle. One is that Josephus was one of a group of Jews who were about to be captured by the Romans. Rather than be enslaved, they chose to commit suicide. They arranged themselves in a circle and, starting at a certain person, started counting off around the circle.
- permutation for the generalized Josephus problem. Our new algorithm can also be applied to a more general case of the generalized Josephus problem where the lives for all objects can be different. The time and space complexities of new algorithms are O(lnlogk) and O(n) respectively. The computational experiments demonstrate that the achieved results are not only of theoretical interest, but.
- Josephus Problem . Our last example is the Josephus problem, named for Flavius Josephus, a famous Jewish historian who participated in and chronicled the Jewish revolt of 66-70 C.E. against the Romans. Josephus, as a general, managed to hold the fortress of Jotapata for 47 days, but after the fall of the city he took refuge with 40 diehards.
- The First
**Algorithm**is the solution to the**Josephus****Problem**. The**problem**is based on a tale during the Roman Empire, 41 jews were hiding in a cave and were about to be captured by the Romans but the jews preferred suicide over surrender and hence devised a strategy. They all would stand in a circle and every third person would be killed

The General Algorithm for Josephus Problem We can attempt to bring the algorithm to a nicer form. It cannot be brought to a closed form (but for the case of = 2), due to the ceiling function that we perform on every phase. However - we can still tidy-up the algorithm. Let us recursively define: These numbers do not have a nice form but for = 2, but if we agree to. We described 2 m loosely as the largest power of two less than or equal to n, but that is an algorithmic description. Described mathematically, m is the integer part of the base 2 logarithm of n; that is, m = floor(log 2 (n)), or . So now we have a formula in terms of the number of participants n: Summary. An alternating elimination Josephus problem has a deep connection to the powers of. In this paper, an image encryption algorithm based on a hyperchaotic system and variable-step Josephus problem is proposed. Based on an in-depth analysis of the classic Josephus problem, a new variable-step Josephus problem that combines the pseudorandom sequence with the Josephus problem is proposed. Firstly, the hash value of the plaintext image is calculated, which is converted to the. TechniFul - stands for Tech..Useful. Posts relate to : Mac, Android, Windows 8, JAVA, iOS, Ubuntu, Web development, templates et

- The proposed solution to avoid these problems, is the proposed new image encryption algorithm based on hyperchaotic systems and the Josephus problem. This paper presents a new satellite image encryption algorithm based on the combination of LFSR generator, SHA 512 hash function, hyperchaotic systems, and Josephus problem
- 1. You are given two numbers N and K. 2. N represents the total number of soldiers standing in a circle having position marked from 0 to N-1. 3. A cruel king wants to execute them but in a different way. 4. He starts executing soldiers from 0th position and proceeds around the circle in clockwise direction. 5
- (The Josephus Problem.) There are \(n\) men arranged in a circle. Beginning with a particular position, we count around the circle and brutally execute every \(m^{th}\) man (the circle closing as men are decapitated). For example, the execution order when \(n = 8, m = 4\) is \(54613872\): the first man is fifth to go, the second man is fourth, etc. Write a program which prints outs the order.

Tried, Tested, Trusted and Affordable for All qPCR Needs Josephus' Problem. Algorithm description. This algorithm is named for a historian of the first century, Flavius Josephus, who survived the Jewish-Roman war due to his mathematical talents. Legend has it that he was one out of 41 Jewish rebels trapped by the Romans. His companions preferred suicide to escape, so they decided to form a cycle and to kill every third person and to proceed around. I came across this interesting algorithm called the Josephus Problem while doing some research, and it really started to make me think about how I approach problem-solving. At the start, the problem presented was seemingly quite difficult to solve, however the more I worked through the problem I found the solution could be eloquently expressed with a few lines of code. Oh look a tree made.

Abstract The Josephus Problem can be described as follows: There are n objects arranged in a circle. Beginning with the first object, we move around the circle and remove every m th object. As each object is removed, the circle closes in. Eventually, all n objects will have been removed from the circle. The order in which the objects are removed induces a permutation on the integers 1 through n present a new fast algorithm to calculate j(n, k, i ) which is based upon the mentioned bounds. 1. Introduction The Josephus problem in its original form goes back to the Roman historian Flavius Josephus (see [3]). In the Romano-Jewish conflict of 67 A. D., the Romans took the town Jotapata which Josephus was commanding. He and 40 companions escaped and were trapped in a cave. Fearing capture. Josephus problem. Posted by Kyriakos Sourmelis January 24, 2021 Posted in algorithms, complexity, programming Tags: algorithm, bitwise, c++, circle, cplusplus, josephus, lastmanstanding, math, maths, operation, Problem, soldiers. There are a lot of cool problems in Mathematics out there. I usually tackle the weird and the strange, but for today's post, I chose a problem that I saw through a. Josephus Problem [1] is a classic mathematical puzzle where there are [math]n [/math] people standing on a circle and an executioner kills every [math]k[/math] th alive person and this goes on until only one person is left on the circle. The targe.. Das Josephus-Problem oder die Josephus-Permutation ist ein theoretisches Problem aus der Informatik oder Mathematik.. Es werden nummerierte Objekte im Kreis angeordnet; dann wird, beginnend mit der Nummer , jedes -te Objekt entfernt, wobei der Kreis immer wieder geschlossen wird.Die Reihenfolge der entfernten Objekte wird als Josephus-Permutation bezeichnet

- Josephus problem is a historical algorithmic problem, which is used for educational purposes in algorithm analysis books and courses. There's a simple algorithm to solve this problem, however the answer can also be found using a formula. Josephus problem can be extended to form Extended Josephus Problem. No formula had been seen for solving this problem before. This paper proposes and proves.
- The Josephus Problem The problem is named after Flavius Josephus, a Jewish historian living in the 1st century. According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers. They chose suicide over capture, and settled on a serial method of committing suicide by drawing lots. Josephus states that by luck or possibly by the hand of God.
- Josephus-Problem Der jüdische Historiker Josephus Flavius (37-95) berichtete davon, dass er mit 40 anderen Juden vor den Römern in einen Keller flüchtete. Um dem Feind nicht in die Hände zu geraten, beschlossen sie sich gegenseitig umzubringen; nur Josephus war dagegen. Deshalb schlug er vor, sich in einem Kreis aufzustellen und jeweils jeden Dritten auf der Stelle zu erschlagen. Da er.

- Algorithm to solve the Josephus Problem. In computer science and mathematics, the Josephus problem (or Josephus permutation) is a theoretical problem related to a certain counting-out game. People are standing in a circle waiting to be executed. Counting begins at a specified point in the circle and proceeds around the circle in a specified direction. After a specified number of people are.
- Generilizations of the Josephus problem Nicolas Th eriault Abstract. This article presents two algorithmic solutions to an extended version of the Josephus problem. In addition, the number of steps required for one of these algorithms is discussed. Finally, a variation on the Josephus problem and an algorithmic solution to this new problem are also given. 1 Introduction Let be given n players.
- Josephus problem pseudocode algorithm. Josephus Problem [ 1] is a classic mathematical puzzle where there are n people standing on a circle and an executioner kills every k th alive person and this goes on until only one person is left on the circle. The target is to find the initial position of the last living person. For example, if n = 5 a n d k = 2. As an example computation, Halbeisen and.
- 使用程式來求解的話，只要將陣列當作環狀來處理就可以了，在陣列中由計數1開始，每找到三個無資料區就填入一個計數，直而計數達41為止，然後將陣列由索引1開始列出，就可以得知每個位置的自殺順序，這就是約瑟夫排列，41個人而報數3的約琴夫排列如下所示

Josephus Flavius Problem Recursive Solution. A recent letter from a math teacher reminded my that the recursive solution I have been planning to describe for a while now is long overdue.. This solution applies to the case where every other person is executed (m = 2) until only one is left (r = 1, see the complete solution.). After the first go-round we essentially come up with the same problem.

- Ternary Search Algorithm; Josephus Problem; Sum of divisors of n^m; Trailing Zeroes of nCr*p^q; Prime Factorization of N! Sum of SOD of all numbers in range 1 to N; Matrix Exponentiation : Problems; Blog Status. 12,096 Views; Create a website or blog at WordPress.com. s search c compose new post r reply e edit t go to top j go to the next post or comment k go to the previous post or comment o.
- The principle of Josephus problem is used to shuffle the image pixels to different positions to achieve the confusion property. Using a randomly generated filter, the filtering technology can spread slight changes of the original image to all pixels of the cipher image to obtain diffusion property. The simulation results show that the developed image encryption algorithm is able to encrypt.
- Josephus problem Easy Accuracy: 52.47% Submissions: 38093 Points: 2 . Given the total number of persons n and a number k which indicates that k-1 persons are skipped and k th person is killed in circle in a fixed direction. The task is to choose the safe place.
- Algorithm Gossip: 約瑟夫問題（Josephus Problem） 說明 據說著名猶太歷史學家 Josephus有過以下的故事：在羅馬人佔領喬塔帕特後，39 個猶太人與Josephus及他的朋友躲到一個洞中，39個猶太人決定寧願死也不要被敵人到，於是決定了一個自殺方式，41個人排成一個圓圈，由第1個人 開始報數，每報數到第3人該人.

** Open Digital Education**.Data for CBSE, GCSE, ICSE and Indian state boards. A repository of tutorials and visualizations to help students learn Computer Science, Mathematics, Physics and Electrical Engineering basics. Visualizations are in the form of Java applets and HTML5 visuals. Graphical Educational content for Mathematics, Science, Computer Science. CS Topics covered : Greedy Algorithms. The Josephus problem (or Josephus permutation) is a theoretical problem related to a certain counting-out game. The problem is described as below. People are standing in a circle waiting to be executed. Counting begins at a specified point in the circle and proceeds around the circle in a specified direction. After a specified number of people. A New Algorithm for the Josephus Problem Using Binary Count Tree Jian Lia, Yanzhou Mab, Zesheng Gaoc and Xinyu Huc Luoyang Campus of the PLA Information Engineering University, Luoyang, China amaomaotfntfn@163.com, bmyz827@126.com, chuxinyu1002015@163.com Abstract. This paper presents a new efficient algorithm for the Josephus problem using Binar

The Josephus Problem asks where to start taking out every kth person in the circle consisted of n people, such that you are the last survivor. The following recursive formula is given: $$\begin{align} f(1,k)&=1, \\ f(n,k)&=((f(n-1,k)+k-1) \bmod n )+1. \end{align}$$ But this is not enough explanation, so I don't get where does it come from. Can anyone help? combinatorics recursion. Share. * Through the above process, we get the image encryption algorithm based on double chaotic cycle shift and Josephus problem (JP-DCCS)*. In the simulation experiment and security analysis, we compare.

In this lesson, we will learn how to solve the Josephus Problem using a circular linked list in Python Das Problem wurde nach dem jüdischen Historiker Flavius Josephus benannt, welcher sich 67 n. Chr. beim Kampf um die galiläische Stadt Jotapata mit 40 weiteren Männern in einer Höhle vor den Römern versteckt hielt (insgesamt also 41 Personen). Er berichtet darüber in seinem Buch Jüdischer Krieg (Buch 3, Kapitel 8). Als das Versteck verraten wurde, forderten die Römer sie auf sich in. Time limit: 1.00 s Memory limit: 512 MB Consider an algorithm that takes as input a positive integer $n$. If $n$ is even, the algorithm divides it by two, and if $n.

Really like this problem, btw i also got issues with those test cases James on 21 Jun 2013 I made the Decimation problem referenced above, and I had problems with my test suite as well Hi all, To gain experience with JavaFX and with the Spring framework I've written this small application which is a graphical representation of the Josephus problem: Given a group of n people arranged in a circle under the edict that every nth person will be executed going around the circle until only one remains, find the position L(n,m) in which you should stand in order to be the last survivor Josephus problem: It is the problem in which n people sits on a table and there is elimination of the kth next element. Like for example Eg. if n = 5 and k iCode Algorithms notes Menu Skip to content. Home; About; Contact; Resume; Josephus problem. 2 Replies. Hey folks, Today we are going to talk about the josephus problem and a codechef problem which is a variant of it. Josephus problem. This game is a modern-day equivalent of the famous Josephus problem. Based on a legend about the famous first-century historian Flavius Josephus, the story is told that in the Jewish revolt against Rome, Josephus and 39 of his comrades held out against the Romans in a cave. With defeat imminent, they decided that they would rather die than be slaves to the Romans. They arranged themselves in a. This paper introduces a new satellite image encryption algorithm based on the Linear Feedback Shift Register (LFSR) generator, SHA 512 hash function, hyperchaotic systems, and Josephus problem. LFSR generates a matrix that is used to construct the 512-bits value of the hash function. These bits are used to set the initial values and parameters of the proposed encryption algorithm. Firstly, the.

The Josephus Problem is a well-established problem in computer science. From Wikipedia: People are standing in a circle waiting to be executed. Counting begins at a specified point in the circle and proceeds around the circle in a specified direction. After a specified number of people are skipped, the next person is executed. The procedure is repeated with the remaining people, starting with. Solving Josephus problem using Java 17th Mar, 2020 17th Mar, 2020 Soumitra The Josephus problem (or Josephus permutation) is a theoretical problem related to a certain counting-out game CodeChef - A Platform for Aspiring Programmers. CodeChef was created as a platform to help programmers make it big in the world of algorithms, computer programming, and programming contests.At CodeChef we work hard to revive the geek in you by hosting a programming contest at the start of the month and two smaller programming challenges at the middle and end of the month The problem is named after Flavius Josephus, a Jewish historian living in the 1st century. According to Josephus' account of the siege of Yodfat, he and his 40 soldiers were trapped in a cave by Roman soldiers. They chose suicide over capture, and settled on a serial method of committing suicide by drawing lots. Josephus states that by luck or possibly by the hand of God, he and another man. The problem here is based on a special case of the famous Josephus problem. We have already discussed the Josephus problem in our recursion section, here we will try to implement the special case of Josephus using bit manipulation. Let us try to understand the problem better with the help of an example. Here we have n = 6, and now we try to.

The encryption algorithm follows the classical diffusion and confusion structure. The principle of the Josephus problem is used to shufﬂe image pixels to different positions to achieve the. The **Josephus** **Problem** doesn't end here. There are a lot of variants on how the process is executed, and there are a lot of questions you can ask about the setup. First, what if we skip a person? In the original setup, we assumed the first person killed the very next person, the second person, in line, and so on, with each person killing the very next person. What if the first person skipped. This is Josephus Problem. Consider there are 10 persons. They would like to choose a leader. The way they decide is that all 10 sit in a circle. They start a count with person 1 and go in clockwise direction and skip 3. Person 4 reached is eliminated. The count starts with the fifth and the next person to go is the fourth in count. Eventually, a single person remains Josephus Algorithm. The problem is described as, If there are n persons standing in a circle. Beginning from any person, the others are numbered in a particular direction (clockwise or anti-clockwise). Then a random number, n is generated. The counting begins from the person numbered as one upto n. The nth person is removed from the game so that total number of persons in the circle gets.

Recently, while solving a problem, I came across the Josephus Algorithm.The problem has different approaches and thus has varied time complexities. The History. The problem is named after Flavius. Algorithms, Programming, Enigma Discussion. May 3, 2014 . Josephus Problem (Circular Lists) By saracogluahmet '''Josephus Problem: A Circular List Example. The problem is this: The soldiers have come together in a circular way, and from the beginning M soldiers are counted and Mth soldier leaves the camp. This counting goes on untill there will be M-1 soldiers. Initially, N soldiers are there. Image Encryption Using Josephus Problem and Filtering Diffusion ZHONGYUN HUA , (Member, IEEE), BINXUAN XU, FAN JIN, AND HEJIAO HUANG , (Member, IEEE) School of Computer Science and Technology, Harbin Institute of Technology, Shenzhen 518055, China Corresponding author: Hejiao Huang (huanghejiao@hit.edu.cn) This work was supported in part by the National Key Research and Development Program of. A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions

I have been reading generalized Josephus problem from Concrete Mathematics. The recurrence form for the problem is given as. f(1) = a f(2n) = 2f(n) + b, for n >= 1 f(2n+1) = 2f(n) + y, for n >= 1 The closed form is given as. f(n) = A(n)a + B(n)b + C(n)y where, A(n) = 2^m B(n) = 2^m-1-l C(n) = l The book then says. Next, let's use recurrence and solution in reverse, by starting with a simple. Josephus-Problem. 8 Beiträge • Seite 1 von 1. el_primo Windoof-User Beiträge: 38 Registriert: 7. Nov 2005 23:42. Josephus-Problem. Prepare for your technical interviews by solving questions that are asked in interviews of various companies. HackerEarth is a global hub of 5M+ developers. We help companies accurately assess, interview, and hire top developers for a myriad of roles The encryption algorithm follows the classical diffusion and confusion structure. The principle of Josephus problem is used to shuffle the image pixels to different positions to achieve the confusion property. Using a randomly generated filter, the filtering technology can spread slight changes of the original image to all pixels of the cipher image to obtain diffusion property. The simulation. Tag Archive: Josephus problem. Implementation of a circular list for solving the problem of Josephus. Filed under: Articles, Data Structures & Algorithms — Leave a comment. October 2, 2010 . For the representation of individuals arranged in a circle, we create a circular linked list with a combination of each person to the person on his left in the circle. The integer i represents the i-th.

2. Solve Josephus problem for a range of values. > java josephus 10 20 10 5 11 7 12 9 13 11 14 13 15 15 16 1 17 3 18 5 19 7 20 9 . 3. Solve the Josephus problem for a single value, but display the state of the line after each shooting. Here the option -a indicates that we need to show all steps in the process. See Josephus.java for more. Extending the Josephus Problem and Its Application in Game Theory Nitesh Naik, John Veigas, K Chandrasekaran National Institute of Technology Karnataka, India { naiknitesh22gec05, john.veigas, kchnitk}@gmail.com Abstract. In this paper we present the Josephus problem that is a part of algorithm analysis used to solve many problems related to circular operations. There is a simple algorithm. From Algorithms in C, Third Edition. The Josephus problem is a counting problem. The goal of the problem is to select one leader out of a group of N people, who are all arranged in a circle. The people take turns counting out M people each turn; the Mth person counted is removed from the circle. The selection then continues with the next person, who counts out another M people, with the Mth. Josephus Problem. This PDF shows How to solve Josephus problem using queue , made up of two stacks. Rhythm Gupta. February 14, 2012 Tweet Share More Decks by Rhythm Gupta. See All by Rhythm Gupta . itsrg 1 20. itsrg 1 140. Other Decks in Programming . See All in Programming. Josephus Problem. Problem #32 Tags: classical loops data-structures. Who solved this? Also available in: Russian. Here is the classical programming puzzle though it came from ancient times when there are no computers at all. We can see that practicing math and logic can sometimes save one's life! About 2000 years ago there was some war, and during one of its battles defendants were blocked by.

Mar 13, 2016 algorithm kotlin Feedback on the Josephus problem. My last week article was about the solving the Josephus problem in Kotlin. For ease of comparison, here's the version I wrote originally: class Soldier(val position: Int) { var state = State.Living lateinit var next: Soldier fun suicide() { state = State.Dead } fun isDead() = state == State.Dead } enum class State { Living, Dead. Mar 6, 2016 algorithm kotlin Solving the Josephus problem in Kotlin. I recently stumbled upon a post telling about the Josephus problem and trying to solve it in different scripting languages. For the sake of brevity, here's the problem (taken from the referenced post): Flavius Josephus was a roman historian of Jewish origin. During the Jewish-Roman wars of the first century AD, he was in a. The Josephus Problem for a step size of \(m = 2\) can be solved two ways: Algorithm D: Doubling Permutation Algorithm; Algorithm S: Label Skipped Nodes Algorithm; In this blog post we cover Algorithm D, which makes use of a doubling permutation. In the first section (Algorithm D: Using Doubling Permutation) we start by showing the recipe as applied to the case of \(n = 11, m = 2\). The recipe. Josephus problem is a math puzzle with a grim description: n prisoners are standing on a circle, sequentially numbered from 0 to n − 1.. An executioner walks along the circle, starting from prisoner 0, removing every k-th prisoner and killing him.. As the process goes on, the circle becomes smaller and smaller, until only one prisoner remains, who is then freed The problem of Josephus is the following. We are given two positive integers n, q. There are n places arranged around a circle, and numbered clockwise 1, 2, , n. Each of n people takes one of the places, then (please excuse this, but we didn't invent the problem!) every q th one is executed, until just one remains. More precisely, the occupant of place q is 'removed' first, and in. The Josephus problem involves n people standing in a circle. Each person kills the next person until there is only one person remaining. We will use a circular linked list to solve the Josephus problem